1.

Calculate the mole fraction of benzene in solution containing 30% by mass in CCl_4

Answer»

Solution :Mass of solution =100G
Mass of BENZENE = 30G
Number of moles of benzene = (Mass)/(Molar mass) = 30/78 = 0.385
Mass of `CCl_4` = 100-30 = 70G
Number of moles of `CCl_4`= (Mass)/(Molar mass) = 70/154 = 0.458
`therefore` MOLE fraction of benzene =(Number of moles of `C_6H_6`)/(Total number of moles)= `0.385/(0.385+0.455) = 0.458`


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