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Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride. |
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Answer» Solution :`30%` of benzene in carbon tetrachloride by mass means that Mass of benzene in the solution = 30 g , `""` Mass of solution = 100 g `therefore""` Mass of carbon tetrachloride `=100-30g=70g,""` MOLAR mass of benzene `(C_(6)H_(6))="78 g mol"^(-1)` `"Molar mass of CCl"_(4)=12+4xx35.5="154 g mol"^(-1)` `therefore"No. of moles of benzene"=("Mass")/("Molar mass")=("30 g")/("78 g mol"^(-1))=0.385` `"No. of moles of CCl"_(4)=("Mass")/("Molar mass")=("70 g")/("154 g mol"^(-1))=0.455` `"Mole fraction of benzene "=("Moles of benzene")/("TOTAL moles in the solution")=(0.385)/(0.385+0.455)=(0.385)/(0.84)=0.458` `"Mole fraction of CCl"_(4)=1-0.458=0.542` |
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