1.

Calculate the molarity of pure water. Given that density of pure wateris 1 g/mol.

Answer»


Solution :`"Mass of 1000 mL of pure water "= Vxxd=(1000 mL)XX(1g//mL)=1000 g`
`"Moles of water in 1000 g"=("Mass")/("Molar mass")=((1000g))/((18" g mol"^(-01)))=55.55 mol`
`"Molarity (M) "=("Moles of water")/("Volume of WASTER in litres")=((55.55 mol))/(1L)`
=55.55 mol/L = 55.55 M.


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