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Calculate the molarity of pure water (d = 1 g mL^(-1)) |
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Answer» SOLUTION :DENSITY of water = `1 g mL^(-1)` Mass of 1000 ml of water = `V xx d` `=1000 m L xx 1 gm^(-1)` `=1000 g` Moles of water = `(1000)/(18) = 55.55` mol Now mole of `H_(2) O ` present in 1000 mL or 1 L of water . So , molarity = 55.55 M |
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