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Calculate the molarity of each of the following solutions :30 g of Co(NO_(3))_(2).6H_(2)O in 4.3 L of solution |
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Answer» SOLUTION :MOLARITY is given by : Molarity `= ("Moles of solute")/("Volume of solution in litre")` Moles of `Co(NO_(3))_(2).6H_(2)O` `=59+2(14+3xx16)+6xx18` `=291 g mol^(-1)` `therefore` Moles of `Co(NO_(3))_(2).6H_(2)O` `=(30)/(291)=0.103` mol Therefore, molarity `= (0.103 mol)/(4.3 L)` |
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