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Calculate the molarity of each of the following solutions :30 mL of 0.5 MH_(2)SO_(4) diluted to 500 mL. |
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Answer» Solution :NUMBER of MOLES PRESENT in 1000 mL 0.5 M `H_(2)SO_(4)=0.5` mol `therefore` Number of moles present in 30 mL of 0.5 M `H_(2)SO_(4)=(0.5xx30)/(1000)` mol = 0.015 mol Therefore, MOLARITY `= (0.015)/(0.5L)` mol = 0.03 mol. |
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