1.

Calculate the molarity of each of the following solution : (a) "30 g of Co "(NO_(3))_(2).6H_(2)Oin 4.3 L of solution (Atomic mass of cobalt = 58.7)

Answer»

Solution :(a) Molar MASS of `Co(NO_(3))_(2).6H_(2)O=58.7+2(14+48)+6xx"18 g mol"^(-1)`
`=58.7+124+"108 g mol"^(-1)="290.7 g mol"^(-1)`
`"No. of moles of "Co(NO_(3))_(2).6H_(2)O=("Mass")/("Molar mass")=("30 g")/("290.7 g mol"^(-1))=0.1032`
`"Volume of solution = 4.3 L"`
`"Molarity of solution "=("No. of moles of solute")/("Volume of solution in L")=("0.1032 mole")/(4.3 L)=0.024 M`


Discussion

No Comment Found

Related InterviewSolutions