1.

Calculate the molarity of each of the following solution : "30 mL of 0.5 M "H_(2)SO_(4) diluted to 500 mL. (Atomic mass of cobalt = 58.7)

Answer»

Solution :(b) 1000 ML of 0.5 M `H_(2)SO_(4)` contain `H_(2)SO_(4)="0.5 mole"`
`therefore"30 mL of 0.5 M "H_(2)SO_(4)" contain "H_(2)SO_(4)=(0.5)/(1000)xx"30 mole = 0.015 mole"`
`"VOLUME of solution = 500 mL = 0.500 L"`
`therefore"Molarity of solution"=("No. of moles of SOLUTE")/("Volume of solution in L")=("0.015 mole")/("0.500 L")="0.03 M"`


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