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Calculate the molarity of a solution containing 5g of NaOH in 450 mL solution. |
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Answer» SOLUTION :Moles of `NaOH = (5G)/(40 mol^(-1))=0.125 mol` Volume of the solution in liters `= 450 mL//1000 mL L^(-1)` Molarity `= (0.125 mol xx 1000 mL L^(-1))/(450 mL)=0.278 M` `= 0.278 mol L^(-1)` `= 0.278 mol DM^(-3)` |
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