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Calculate the molarity of 9.8% (W/W) solutionof H_(2)SO_(4) if the density of solution is 1.02 g mL^(-1) (Molar mas of H_(2)SO_(4)=98 g mol^(-1)). |
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Answer» Mass of solution = 100 g Mass of solute = 9.8 g `"Density of the solution" = 1.02 " g mL"^(-1)` `"Volume of the solution"=("Mass of solution")/("Density of solution")` `=((100g))/((1/02"g mL"^(-1))=98.04 mL = 0.098 L.` `"Molarity of solution (M)"=("Mass os solute/Molar mass of solute")/("Volume of solution in litres")` `((9.8g)//(98" g mol"^(-1)))/((200//1000)L)=0.5 mol L^(-1)=1.02 M.` |
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