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Calculate the molarity and molarity of a solution of ethanol in water if the molre fraction of ethanol is 0.05 and the density of solution is 0.997 g/"cc" |
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Answer» Solution :SINCE mole fraction of `C_(2)H_(5)OH=("MOLES of " C_(2)H_(5)OH)/("moles of" C_(2)H_(5)OH+"moles of " H_(2)O)` `=0.05=(5)/(100)` `:.100` moles of solution contain 5 moles of `C_(2)H_(5)OH` Weight of `C_(2)H_(5)OH=` moles `xx`mol.wt. `=5xx46=230g` Weight OG `H_(2)O=95xx18=1710g` `:.` weight of solution `=230+1710=1940g` Volume of solution `=(1940)/(0.997)"cc"=1945.8mL=1.9458` litres `:.` molality `=(5)/(1710)xx1000=2.92m` Molarity `=(5)/(1.9458)=2.57M` |
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