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Calculate the molarity and molality of9.8 (w/w) solution of sulphuric acid.give the density of solution is 1.02g/ml |
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Answer» M (Molarity )= 0.980 M m (molality ) = 1.10 m Explanation: W/w=9.8%, w (solute)= 9.8g W(solvent) = 90.2 g w(SOLUTION)=100 g M = w/M.M. = 9.8/ 98 ------------- ×1000 ------------ ×1000 = 0.980 M V ( ML) 100×1.02 m = w/M.M 9.8 /98 ----------- × 1000 = --------------- ×1000 = 1.10 m W (g) ( 100 - 9.8) |
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