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Calculate the molar mass of the following (a) CHCl3 (b)CH3COOH (c)C12H22O11 |
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Answer» CHCl3=12+1+(3×35.5)=13+106.5=119.5uCH3COOH=12+(3×1) +12+16+16+1=60uC12H22O11=(12×12) +(22×1)+(11×16)=144+22+176=344u |
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