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Calculate the molar conductance of 0.01M aqueous KCl solution at 25^(@)C. The specific conductance of KCl at 25^(@)C is 14.114 times 10^(-2)Sm^(-1). |
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Answer» Solution :MOLAR conductance `wedge_(m)=(KAPPA times 10^(-3))/Mmol^(-1)m^(3)` Specific conductance `kappa=14.114 times 10^(-2)Sm^(-1)` Molar conductance `wedge_(m)=(14.114 times 10^(-2) times 10^(-3))/(0.01)` `""=14.114 times 10^(-3)Sm^(2)MOL^(-1)`. |
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