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Calculate the molality of H_(2)SO_(4) if the density of 10% (w/w) aqueous solution of H_(2)SO_(4) is 1.84 "g cm"^(-3) ("Molar mass of "H_(2)SO_(4)="98 g mol"^(-1)). |
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Answer» Solution :10%` (w//w) H_(2)SO_(4)` solution MEANS 10 G `H_(2)SO_(4)` are PRESENT in 100 g of solution, i.e., water present = 90 g `"Molality "=(10//98)/(90)xx1000=1.13m` |
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