1.

Calculate the molality of a solution that contains 51.2 g of naphthanlene (C_(10)H_(18)) in 500 mL of carbon tetrechloride. Density of C CL_(4) is 1.60 g/ml

Answer»

0.250 m
0.500 m
0.840 m
1.69 m

Solution :`"Mass of" C CI_(4)(W_(A))="Volume "xx"density "`
`=(500ML)xx(1.60 G mL^(-1))=800G =0.8 kg`
`"Molality of "C CI_(4)(m)=("No.ofmoles of napthalene")/("Mass of "C CI_(4)"in kg")`
` =((51.2g)//(128 g mol^(-1)))/((0.8 kg))`
0.5 `mol kg^(-1)=0.5 m`


Discussion

No Comment Found

Related InterviewSolutions