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Calculate the molality of a solution prepared by dissolving 47.5g of MgCl2 in 200g of water |
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Answer» moles of MgCl2 = 4.75/95= 0.05molality = NUMBER of moles of solute/ mass of SOLUTION in SOLVENT (in kg)mass of solvent = 200/1000molality = 0.05 / (200/1000)MOLALITY = 0.5 / 2molality = 0.25 mhope this will help you |
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