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Calculate the molality of 9.8% (w/w) solution of sulphuric acid. Given the density of solution is 1.02g/ml |
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Answer» means 9.8gr in 100gr of solution the MASS of solvent is 100-9.8=90.2 gr molality=mass of SOLUTE/molar mass of solute*1000/mass of solvent=9.8/98*1000/90.2=1.108molality (m)HOPE so helpful. |
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