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Calculate the molality of 45 gm of HNO3 dissolved in 80 gm of h2o |
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Answer» Moles of HNO₃ = 45 g / (45 g/mol) =2.0160 H (2*1.008) + 15.9990 O (1*15.999) molWeight of solvent = 750 g = 0.80kgMolality = Moles of solute / Weight of Solvent in KG= 2.5 mol / (0.80kg)=3.125 ANS |
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