Calculate the molality of 1 litre solution of 93% H_(2)SO_(4) (weight – InterviewSolution

1.	Calculate the molality of 1 litre solution of 93% H_(2)SO_(4) (weight / volume). The density of the solution is "1.84 g mL"^(-1).
Answer» Solution :`93% H_(2)SO_(4)(w//v)=93 g H_(2)SO_(4)" in 100 cm"^(3)" of the solution = 93 g in 184 g of the solution"` `therefore"Solvent (water) "=184-93 = 91 g = 0.091 kg,"Molality "=("93/98 mol")/("0.091 kg")=10.43 m.`

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