1.

Calculate the molal elevation constant of water, it being given that its latent heat of vaporisation is 2.257 kJ//g.

Answer»

SOLUTION :`K_(b)=(RT_(0)^(2))/(1000l_(v))=(8.314JK^(-1)"mol"^(-1)xx(373K)^(2))/(1000gkg^(-1)xx2257Jg^(-1))="0.512 K KG mol"^(-1)`


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