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Calculate the molal elevation constant of water, it being given that 0.1 molal aqueous solution of a substance boiled at 100.052^(@)C. |
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Answer» Solution :Here, we are GIVEN that m = 0.1 Boiling point of solution `= 100.052^(@)C "" therefore "" Delta T_(B)=100.52-100=0.052^(@)C` APPLYING the relationship, `Delta T_(b)=K_(b)`. m, we GET `K_(b)=(Delta T_(b))/(m)=(0.052^(@)C)/(0.1 m)=0.52^(@)C//m` |
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