1.

Calculate the molal depression constant of a solvent which has freezing point 16.6^(@)C and latent heat of fusion 180.75 Jg^(-1)

Answer»

`2.68`
`3.86`
`4.68`
`2.86`

SOLUTION :`K_(f)=(RT_(f)^(2))/(1000xx L_(f)), R=8.314 JK^(-1)MOL^(-1)`
`T_(f)=273+16.6=289.6K , L_(f)=180.75 JG^(-1)`
`K_(f)=(8.314xx289.6xx289.6)/(1000xx180.75)=3.86`


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