1.

Calculate the minimum uncertainty in velocity of a particle of mass 1.1 xx 10^(-27) kg if uncertainty in its position is 3 xx 10^(-10)cm. (h= 6.62 xx 10^(-34)kg.m^(2) s^(-1))

Answer»

Solution :We have, `Deltax.Deltap= (h)/(4pi)`
`DELTA x. (m Delta V)= (h)/(4pi)`
or `Delta v= (h)/(4pi) .(1)/(m Delta x)`
`=(6.62 xx 10^(-34) (kg.m^(2)s^(-1)))/(4 xx 3.14 xx (1.1 xx 10^(-27)kg) xx (3 xx 10^(-12) m))`
`=1.6 xx 10^(4) ms^(-1)`


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