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Calculate the minimum and maximum number of electrons which may have magnetic quantum number `m=+1` and spin quantum number `s=-(1)/(2)` in chromium (Cr)A. 0,1B. 1,2C. 4,6D. 2,3 |
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Answer» Correct Answer - D `[Cr]=1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(1)3d^(5)` For `pl=1` `m=+1,0,-1` For 2p of 3p there are 2e with `s=-(1)/(2)` for dl=2 m=+1 may have e with `+(1)/(2)` or `-(1)/(2)` So manimum 2 and maximum 3. |
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