calculate the maximum work done in expanding 16 g of oxygen at 300K and occupying a volume of 5 dm^3 isothermally until the volume becomes 25 dm^3.

calculate the maximum work done in expanding 16 g of oxygen at 300K an

1.	calculate the maximum work done in expanding 16 g of oxygen at 300K and occupying a volume of 5 dm^3 isothermally until the volume becomes 25 dm^3.
Answer» -2.01 x 10(3)EXPLANATION: MAXIMUM work is obtained in isothermal reversible process.The expression for the maximum work is as follows:w=−2.303 NRT logV1V2The number of moles of OXYGEN is NO2=Molecular weight Weight=3216=0.5 The temperature is T =300 KThe INITIAL VOLUME is V1 =5 dm3The final volume is V2 =25 dm3Substituting values in the above reaction, we getw=−2.303×3216×8.314×300×log525=−2.01×103 J

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calculate the maximum work done in expanding 16 g of oxygen at 300K and occupying a volume of 5 dm^3 isothermally until the volume becomes 25 dm^3.​

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calculate the maximum work done in expanding 16 g of oxygen at 300K and occupying a volume of 5 dm^3 isothermally until the volume becomes 25 dm^3.