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Calculate the maximum work and log K_(c)for the given reaction at 298 K : Ni(s)+2Ag^(+)(aq) iff Ni^(2+)(aq)+2Ag (s) ["Given :"E^(@)_(Ni^(2+)//Ni)=-0.25V,E^(@)_(Ag^(+)//Ag)=+0.80V,1F=96500C mol^(-1)] |
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Answer» Solution :`Ni(s)+2Ag^(+)(aq)iff Ni^(2+)(aq)+2Ag(s)` `E^(@)_("cell")=0.80V-(-0.25V)=1.05V` `E^(@)_("cell")=(0.059)/(2)LOG K_(C)` or `""1.05V=(0.059)/(2)log K_(c)` or `""log K_(c)=(1.05xx2)/(0.059)=35.59` `Delta_(R)G^(@)=-NF E^(@)_("cell")` `=-2xx96500C mol^(-1)xx1.05V` `=-202650" J mol"^(-1)` `=-202.65" kJ mol"^(-1)` |
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