Calculate the maximum extension of the spring in the following two cases. Also calculate period of oscillation in each case. (a)

Calculate the maximum extension of the spring in the following two cas

1.	Calculate the maximum extension of the spring in the following two cases. Also calculate period of oscillation in each case. (a)
Answer» Solution :`ma-KY` `"so that"a=(-ky)/(m)"and "(y)/(a)=\|-(m)/(k)\|` Hence `T=2pisqrt((y)/(a))` may be written as`""T=2pi sqrt((m)/(k))` Maximum extension of the spring will be .y. (b) `ma=-2KY` `"so that"(y)/(a)=\|-(m)/(2k)\|""{:("Altermaively"),(mua=-ky),("where "MU=(m_(1)m_(2))/(m_(1)+m_(2))=(m)/(2)):}` `&T=2pisqrt((y)/(a))""{:(THEREFORE (ma)/(2)=-ky),("or ma "=-2ky):}` `T=2pisqrt((m)/(2k))""ma=-k(2y)` Maximum extension of the spring will be .2y..