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Calculate the massof ascorbic acid (Vitamin C, C_(6)H_(8)O_(6)) to be dissolved in 75g of acetic acid to lower its melting point by 1.5^(@)C. K_("f")=3.9" K kg mol"^(-1). Since, lowering of melting point is given apply the formula for lowering of melting point, i.e., DeltaT_("f")=K_("f").m DeltaT_("f")=(K_("f").W_(B))/(M_(B)xxW_(A))" or "W_(B)=(DeltaT_("f").M_(B).W_(A))/(K_("f")) |
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Answer» SOLUTION :Mass of ascorbic acid `(W_(A))=75" g"=0.075" kg"` Depression in melting point `(DeltaT_("F"))=1.5^(@)C=1.5" K"` Molar mass of ascorbic acid `(M_(B))=(12xx6)+(8xx1)+(16xx6)=176" g mol"^(-1)` Molal depression constant `(K_("f"))=3.9" K kg mol"^(-1)` `W_(B)=((176" g mol"^(-1))xx(1.5" K")xx(0.075" kg"))/((3.9" K kg mol"^(-1)))=5.08" g"` |
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