1.

Calculate the mass percentage of benzene (C_6H_6)and carbon tetrachloride (CCl_4) if 22g of benzene is dissolved in 122g of CCl_4

Answer»

SOLUTION :MASS PERCENTAGE of `C_6H_6`=(Mass of `C_6H_6`)/(Mass of solution)`XX100 =(22xx100)/(22+122)=15.28%`
Mass percentage of `CCl_4= (122xx100)/(22+122)=84.72%`


Discussion

No Comment Found