1.

Calculate the mass percentage of benzene (C_(6)H_(6)) and carbon tetrachloride ("CCl"_(4)) if 22 g of benzene is dissolved in 122 g of carbon tetrachloride.

Answer»

Solution :MASS of solution = Mass of BENZENE + Mass of barbon tetrachloride `=22g+122g=144G`
`"Mass percentage of benzene"=("Mass of benzene")/("Mass of solution")xx100=(22g)/(144g)xx100=15.28%`
`"Mass percentage of CCl"_(4)=("Mass of CCl"_(4))/("Mass of solution")xx100=(122)/(144)xx100=84.72%`
Alternatively, mass percentage of `"CCl"_(4)=100-"Mass percentage of benzene "=100-15.28=84.72%`.


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