1.

Calculate the mass per cent of different elements present in sodium sulphate (Na_(2)SO_(4))?

Answer»

Solution :`"Mass "%" of an element"=("Mass of that element in the COMPOUND")/("Molar mass of the compound")xx100`
`"Now, molar mass of "Na_(2)SO_(4)=2(23.0)+32.0+4xx16.0="142 G MOL"^(-1)`
`"Mass PERCENT of sodium"=(46)/(142)xx100=32.39%`
`"Mass per cent of sulphur"=(32)/(142)xx100=22.54%`
`"Mass per cent of oxygen"=(64)/(142)xx100=45.07%`


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