1.

Calculate the mass of NaCI (molar mass =58.5 g mol^(-1)) to be dissoved in 37.2 g of water to lower the freezing point by 2^(@)C assuming that NaCI underfoes complete dissocilation in aqueous solution (K_(f) for water = 1.86 K kg mol^(-1)).

Answer»


SOLUTION :`i=(DeltaT_(f))/(K_(f)xxm)=(DeltaT_(f)xxM_(B)xxM_(A))/(K_(f)xxW_(B))or W_(B)=(DeltaT_(f)xxM_(B)xxM_(A))/(ixxK_(f))`
`i=2("for complete dissciation of NaCI"),K_(f)=1.86" K kg mol"^(-1)`
`DeltaT_(f)=2K, M_(B)=58.5" g mol"^(-1), M_(A)=37.2 g=0.037 kg`
`W_(B)=((2K)xx(58.5"gmol"^(-1))xx(0.037 kg))/(2XX(1.86" K kg mol"^(-1)))=1.16 g`


Discussion

No Comment Found

Related InterviewSolutions