1.

Calculate the mass of Na_(2)CO_(3) which will have the same number of molecules as contained in 12.3 g of MgSO_(4).7 H_(2)O.

Answer»


Solution :`12.3" g MgSO_(4).7H_(2)O=(12.3)/((24+32+64+126))MOL=(12.3)/(246)mol=0.05mol`
`0.05mol Na_(2)CO_(3)=0.05xx106g=5.3g`


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