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Calculate the mass of mercury which can be liberated from HgO at 25^(@)C by the treatment of excess HgO with 41.84 kJ of heat at : (a) constant pressure (b) constant volume Given : Delta H_(f)^(@)(HgO, s) = -90.8 kJ mol^(-1) & M(Hg) = 200.6 g mol^(-1). |
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Answer» For `41.84 KJ` heat, MASS of `Hg=200.6/90.8 xx41.84=-92.435 g` (b) Calculate at constant VOLUME |
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