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Calculate the mass of compound (molar mass = 256 g mol^(-1) ) to be dissolved in 75 g of benzene to lower its freezing point by 0.48 K(K_(f) = 5.12 "Kkg " mol^(-1)) . |
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Answer» SOLUTION :Given : `Delta T_(f) = (K_(f) W_(2) xx 1000)/(W_(1) xx M_(2))` 0.48 K = 5.12 k KG `mol^(-1) xx (W_(2))/(75 xx 256) xx 1000` `W_(2) = (0.48 xx 75 xx 256)/(5.12 xx 1000)` `W_(2) ` = 1.8 g |
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