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Calculate the magnetic moments of the following complexes: (i) [Fe(CN)_(6)]^(-4) (ii)[FeF_(6)]^(-3) |
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Answer» SOLUTION :(i) `Fe^(+2) rightarrow 3d^(6)``CN^(-)` is a strong LIGAND so `E^(-)` pair 4p, no unpaired `e^(-)` then magnetic moment is zero. (ii) `mu_(BH)=sqrt(n(n+2)) = 0` n=5,so `MU=sqrt(n(n+2))` `mu_=sqrt(5(5+2))` `mu=sqrt(35) = 5.96 BM` |
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