1.

Calculate the magnetic moment of Fe^(2+) (At. No. 26)?

Answer»

Solution :`FE^(2+)- 1s^(2)2s^(2)2P^(6)3s^(2)3P^(6)3d^(6)`
No. of unpaired electrons = 4
`:. "Magnetic moment" MU = sqrt(N(n+2))BM`
`= sqrt(4(6))= sqrt(24)= 4.92 "BM"`


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