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Calculate the magnetic moment and the number of unpaired electrons in Cu^(2+). |
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Answer» Solution :Cu (Z = 29) Electronic CONFIGURATION `[Ar]3d^(10) 4S^(1)` `Cu^(2+)` Electronic configuration `[Ar] 3d^(9)` The number of UNPAIRED electrons  is 1.Magnetic moment `mu = sqrt(1(1+2)) = sqrt(3) = 1.732 mu_(B)` |
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