1.

Calculate the linear velocity of the tip of a second switch of length 0.02 metre.​

Answer»

Answer:

the linear velocity of the second's switch is 0.21 cm/s

Explanation:

Length of the SECONDS hand = 0.02 m

Since in 60 seconds the second's hand completes one FULL revolution

Therefore the DISTANCE COVERED in 1 second = 2\pi r

r is the radius which is equal to the length of the second's hand = 0.02 m

Therefore, distance covered in 60 seconds

=2\times\pi\times 0.02

=2\times 3.14\times 0.02

=0.1256 m

Speed = Distance/Time

Speed of the second's hand

=\frac{0.1256}{60}

=2.09\times10^{-3} m/s

=0.21 cm/s

Therefore the linear velocity of the second's switch is 0.21 cm/s

Hope this answer is helpful.



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