1.

Calculate the lattice enthalpy in kJ mol−1of LiF given that Sublimation of lithium is 155.3 kJ mol−1 Dissociation of half mole of F2=75.3 kJ Ionization enthalpy of lithium =520 kJ mol−1 Electron gain enthalpy of 1 mol of F(g) =−333 kJΔfHoverall=−594 kJ mol−1

Answer»

Calculate the lattice enthalpy in kJ mol1of LiF given that
Sublimation of lithium is 155.3 kJ mol1
Dissociation of half mole of F2=75.3 kJ
Ionization enthalpy of lithium =520 kJ mol1
Electron gain enthalpy of 1 mol of F(g) =333 kJΔfHoverall=594 kJ mol1



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