Calculate the kinetic energy per molecule and also rms velocity of a gas at 127^@C . Given k_B = 1.38 xx10^(-23) J "molecule"^(-1) K^(-1)and mass per molecule of the gas =6.4xx10^(-27) kg .

Calculate the kinetic energy per molecule and also rms velocity of a g

1.	Calculate the kinetic energy per molecule and also rms velocity of a gas at 127^@C . Given k_B = 1.38 xx10^(-23) J "molecule"^(-1) K^(-1)and mass per molecule of the gas =6.4xx10^(-27) kg .
Answer» SOLUTION :Here, T = 127 + 23 = 400 K, `m =6.4 xx10^(-27) KG` (i) Kinetic energy per molecule `=1/2mv_(rms)^2=3/2k_BT` `=3/2xx1.38xx10^(-23) xx400` `=8.28xx10^(-21)J` (ii) Now `1/2mv_(rms)^2=8.28xx10^(-21) J` `:.v_(rms)=SQRT(2xx8.28xx10^(-21))/m` `=sqrt((2xx8.28xx10^(-21))/(6.4xx10^(-27)))` `=1.608xx10^3 MS^(-1)`