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Calculate the ionisation energy in eV of a hydrogen atom in the ground state. |
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Answer» SOLUTION :Since IONISATION energy is defined as the energy required to remove an ELECTRON from the outermost orbit of an atom, mathematically, we can say that since the hydrogen atom is in the ground state, ionisation energy will be the energy required to remove the electron from the first orbit to the infinite orbit (i.e., `r_(1)` to `r_(oo)` ), THUS ionisation energy `=E_(oo)-E_(1)` `=0-(-2.18 xx 10^(-11))` erg (`E_(1)= -2.18 xx 10^(-11)`erg) `therefore` ionisation energy `=2.18 xx 10^(-11)` erg `=(2.18 xx 10^(-11))/(1.602 xx 10^(-12))= 13.60eV` (1eV= `1.602 xx 10^(-12)`erg) |
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