Calculate the ionisation constant for the conjugate base of HF. Ionisa – InterviewSolution

1.	Calculate the ionisation constant for the conjugate base of HF. Ionisation constant of HF at 298K is 6.8xx10^(-4).
Answer» SOLUTION :The conjugate base of HF is `F^-` For `F^-. K_b=(K_w)/(K_a)=(10^(-14))/(6.8xx10^(-4))` `=1.47xx10^(-11)`

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