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Calculate the % increase in temperature of gas when it is heated at constant pressure to occupy 20% increase in volume.

Answer»

SOLUTION :`V_(1)=V, T=T_(1), V_(2)=V+(20V)/(100)=(120V)/(100), T=T_(2)`
`THEREFORE` From Charle.s law : `(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`therefore T_(2) =(120 VxxT_(1))/(100xxV) =1.2T_(1)`
`therefore` INCREASE in TEMPERATURE `=1.2 T_(1) -T_(1)=0.2 T_(1)`
`therefore %` increase in temperature `=(0.2T_(1))/(T_(1))xx100=20%`


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