1.

Calculate the ii) degree of hydrolysis and

Answer»

Solution :SODIUM carbonate is a salt of weak acid, `H_2 CO_3` and a strong BASE, `NaOH`, and hence the solution is alkaline due to hydrolysis.
`Na_2 CO_(3(AQ)) to 2Na_((aq))^(+)+CO_(3(aq))^(2-)`
`CO_(3(aq))^(2-)+H_2O(I) hArr HCO_(3)^(-)+OH^(-)`
(ii) `K_(h)=(K_w)/(K_a)=(1xx10^(-14))/(1.8xx10^(-5))`
`=5.56 xx 10^(-10). `


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