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Calculate the hydrogen ion and hydroxyl ion concentration of 0.01 M solution of `NaOH` at 298 K. |
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Answer» `NaOH` is a strong base and is , therefore, completely ionised in water. `{:(NaOH ,overset(aq)(to), Na^(+)(aq) ,+, OH^(-)(aq)),(,,0.01 M,,0.01M):}` `" Thus "" "[OH^(-) (aq)] =[NaOH]=0.01M` `"["H_(3)O^(+)"]" = (K_(w))/[[OH^(-)(aq)]]=((1.0xx10^(-14)M^(2)))/((0.01M)) = 10^(-12)M` |
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