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Calculate the heatof combustion of methaneat roomtemperaturefromthe givenbondeneries: C-H=98.7 kcal /mol o=O = 119.1 kcal /mol C=o = 192.0 kcal /mol o-H = 110.6 kcal /mol |
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Answer» Solution :`CH_(4)+20_(2)=CO_(2)+2H_(2)O DeltaH=? ` `Delta H=` total bond energiesreactants -Totalbond energies products `=[4xx(c-H)+2xx(o=o)]-[2xx(C=O)+4(O-H)]` `=[4xx98.7+2xx119.1-2xx192.0-4xx110.6` `=-193.4 kcal //MOL]` |
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