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Calculate the heat produced in calorie when a current of 0.1A is passed through a wire of resistance 41.8Ω for5 minutes. |
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Answer» Answer: Answer - 125.4J Explanation: Heat PRODUCE = (l)^2 × R × time in SECOND = (0.1)^2 × 41.8 × (5×60) = 0.01 × 41.8 × 300 = 3 × 41.8 = 125.4 J Heat = 125.4 J 1J = 4.2 calories heat = 125.4 /4.2 = 30 calorie ✌️ Hope it's helpful for U ❤️ |
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