1.

Calculate the heat produced in calorie when a current of 0.1A is passed through a wire of resistance 41.8Ω for5 minutes. ​

Answer»

Answer:

Answer - 125.4J

Explanation:

Heat PRODUCE = (l)^2 × R × time in SECOND

= (0.1)^2 × 41.8 × (5×60)

= 0.01 × 41.8 × 300

= 3 × 41.8

= 125.4 J

Heat = 125.4 J

1J = 4.2 calories

heat = 125.4 /4.2

= 30 calorie

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