1.

Calculate the heat of formation of PCl_(5)(s) from the following data : 2P(s) + 3Cl_(2)(g) rarr 2PCl_(3)(l)Delta H = -151.8 kcal PCl_(3)(l) + Cl_(2)(g) rarr PCl_(5)(s)Delta H = -32.8 kcal

Answer»

<P>`-108.7 kcal`
108.7 kcal
`-184.6 kcal`
184.6 kcal

Solution :(i) `2P(s) + 3Cl_(2)(g) rarr 2PCl_(3)(L) Delta H = - 151.8 kcal`
(ii) `PCl_(3)(l) + Cl_(2)(g) rarr PCl_(5)(m) Delta H = - 32.8 kcal`
`P(s) + (5)/(2) Cl_(2)(g) rarr PCl_(5)(s) Delta H = ?`
Dividing equation (i) by 2 and add equation (ii)
`P(s) + (5)/(2) Cl_(2)(g) rarr PCl_(5)(s) Delta H = -75.9 - 32.8 = -108.7 kcal`


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